Spookymuffin said: conch5184 said: I think it's throwing me off that you go to school in Britian, they word things differently... do you go to Eton?
Yes, I go to Eton. Did you ever meet William or Harry? Do you think it's true that there's a lot of homosexual experimentation at Eton? Do you think William probably ever did it with a man? (I'm only curious because gay sex turns me on [This message was edited Sun Jan 18 14:00:07 PST 2004 by conch5184] | |
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Spookymuffin said: JaneyPoos said: Jesus christ! lol How confusings this!
to be honest I didn't hold high hopes for my math skills I tried to help my mates lil sister with her 11+ mock papers the other day (a paper 10-11 year olds ) and I didn't understand it! I have no idea how I got a C for it at GCSE (thats the exams at bout 16 yrs) (brackets are for those who don't know these things!) (MATHS ) dopey nuts edit [This message was edited Sun Jan 18 13:48:32 PST 2004 by JaneyPoos] I take my GCSE this time next year, and this is one of the topics we have to study. My condolences lol edit edit edit edit [This message was edited Sun Jan 18 14:01:03 PST 2004 by JaneyPoos] JaneyPoos used to be it... then they changed what it was. Now what I am isn't it and what is it is strange and frightening to me...
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Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. | |
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Vibrator said: Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. where's y and z? | |
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Vibrator said: Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. Ha! In your face Fermat! | |
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Spookymuffin said: Nope, like I've said before, x must equal something in the form of "x = y or z" - Don't try and break the equation up, it doesn't work. You must Factorise first. Well, it was factorized, and the answer was in the form of x=y or z (y or z being the number). But it seems like you know what you're doing now, sorry... | |
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Raspberry said: Vibrator said: Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. where's y and z? you put each one in the place of x ! | |
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Raspberry said: Vibrator said: Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. where's y and z? She was looking for an answer in the format x = y or z where y and z are unknown. The above tells you what they stand for. | |
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2the9s said: Vibrator said: Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. Ha! In your face Fermat! Have you read Fermat's Last Theorem by Simon Singh? It's a fantastic book, easy to read | |
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conch5184 said: Raspberry said: Vibrator said: Spookymuffin said: 2the9s said: 2 and -.5?
I don't think so, at least not the way I've done it. Actually the answer is correct, if that was all you were looking for. Y=2 and Z=-0,5 (if that´s what you want to name them). Just insert the numbers into the equation and you´ll see. where's y and z? you put each one in the place of x ! That´s right. | |
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So, then, x does not equal "Kentucky"??... :O | |
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Byron said: So, then, x does not equal "Kentucky"??... :O
Sure it does. Didn´t I mention that x = 2 or -0,5 or Kentucky? | |
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2x^2 - 3x - 2 = 0
This is good. You want to find the points where y = 0. You do that by figuring out what numbers X can be to make the equation on the left = 0. (4x + 2) * (.5x - 1) = 0 Lets check our factoring by FOIL (4x * .5x) + (4x * -1) + (2 * .5x) + (2 * -1) =0 Simplify (2x^2) + (-4x) + (1x) + (-2) = 0 Combine like terms 2x^2 + (-4x + 1x) + (-2) = 0 Simplify again 2x^2 - 3x -2 = 0 (it checks as good) So back to our factored out equation: (4x + 2) * (.5x - 1) = 0 What values for X will make the statement True? We know that anything times 0 will equal zero, so how can be make our first set = 0? 4x + 2 = 0 4x = 0 - 2 4x = -2 x = -2 / 4 x = - .5 Also, we can do the same to the second set .5x - 1 = 0 .5x = 0 + 1 .5x = 1 x = 1 / .5 x = 2 So our two answers are { -.5 , 2 } Lets check our answers: 2x^2 - 3x - 2 = 0 2(-.5^2) - (3 * -.5) - 2 = 0 2(.25) + (1.5) - 2 = 0 (important to see the minus change there at the 1.5) .5 + 1.5 - 2 = 0 2 - 2 = 0 0 = 0 CHECK 2(2^2) - (3*2) - 2 = 0 2*4 - 6 - 2 = 0 8 - 6 - 2 = 0 2 - 2 = 0 0 = 0 CHECK Any questions? -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
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Byron said: So, then, x does not equal "Kentucky"??... :O
i dunno...it might equal "washington". hell if i know...i don't even know how to do algebra. and i suck at math(s)... | |
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Spookymuffin said: conch5184 said: I think it's throwing me off that you go to school in Britian, they word things differently... do you go to Eton?
Yes, I go to Eton. I mean, like, where is the sun? | |
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I haven't read everything, but
X = 1 or x = 2 (obviously, cause that's what will make the whole thing zero. The 2 outside the brackets has no influence). "It's better 2 B hated 4 what U R than 2 B loved 4 what U R not."
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Since the two confuses u, i'll xplain:
u factorised the whole thing, right. Now, the righthandside is zero. To get the lefthandside to zero, all u have to do is get one of the factors to zero (since 0 times anything still equals zero). The factors u have are: (2) (x-2) and (x-1) so, the only two factors u can get to zero are (x-2) and (x-1) if u'r confused by the 2, look at it this way: the factors could also b (2x-4) and (x-1), right? u equal one of the factors to zero: 2x - 4 = 0 ; and u still get x = 2 yet another way to factorise: (x-2) and (2x-2) and yet again u get 1 and 2. Yet another solution is to divide each side of the equations by 2. 2/2 = 1 and 0/2 = 0 Capice? [This message was edited Sun Jan 18 16:45:22 PST 2004 by SpcMs] "It's better 2 B hated 4 what U R than 2 B loved 4 what U R not."
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SpcMs said: Since the two confuses u, i'll xplain:
u factorised the whole thing, right. Now, the righthandside is zero. To get the lefthandside to zero, all u have to do is get one of the factors to zero (since 0 times anything still equals zero). The factors u have are: (2) (x-2) and (x-1) so, the only two factors u can get to zero are (x-2) and (x-1) if u'r confused by the 2, look at it this way: the factors could also b (2x-4) and (x-1), right? u equal one of the factors to zero: 2x - 4 = 0 ; and u still get x = 2 yet another way to factorise: (x-2) and (2x-2) and yet again u get 1 and 2. Yet another solution is to divide each side of the equations by 2. 2/2 = 1 and 0/2 = 0 Capice? [This message was edited Sun Jan 18 16:45:22 PST 2004 by SpcMs] Thanks a lot! That's the right answer, there's what I was looking for. THANKYOU! That's my maths homework finished! | |
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conch5184 said: Spookymuffin said: conch5184 said: I think it's throwing me off that you go to school in Britian, they word things differently... do you go to Eton?
Yes, I go to Eton. Did you ever meet William or Harry? Do you think it's true that there's a lot of homosexual experimentation at Eton? Do you think William probably ever did it with a man? (I'm only curious because gay sex turns me on [This message was edited Sun Jan 18 14:00:07 PST 2004 by conch5184] I met Harry. Twice. He's an arrogant little penis, I really hated him; he thought he was so cool cause he was royalty and it got let out in the news that he smoked dope. Truth is, everyone at Eton smokes dope, it's just one of those things. Secondly, no, there was gay "experimentation" as you call it in the 1930s at Eton, but not any more. We have "socials" (trips to visit girls) every Sunday to keep us on the straight and narrow as it were. Not that I'm homophobic, but you can see the media, "Eton made my son turn GAY." So, no, I don't think old William ever did it with a man, nor have I, although there was tons of Sexual experimentation at my last school, which none of you will have heard of. 1st there was the discovery of masturbation when all of us were 11, and everyone was doing it - but then we needed fantasies, so along came searches for porn. After being corrupted by porn, we all kinda wondered what some of the stuff was, like how can head be pleasurable? Anyway, to cut a long story short, many of us tried out giving each other head for a while, including me (well, I got head, but never gave it ) ***** [This message was edited Mon Jan 19 5:18:53 PST 2004 by Spookymuffin] | |
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Spookymuffin said: SpcMs said: Since the two confuses u, i'll xplain:
u factorised the whole thing, right. Now, the righthandside is zero. To get the lefthandside to zero, all u have to do is get one of the factors to zero (since 0 times anything still equals zero). The factors u have are: (2) (x-2) and (x-1) so, the only two factors u can get to zero are (x-2) and (x-1) if u'r confused by the 2, look at it this way: the factors could also b (2x-4) and (x-1), right? u equal one of the factors to zero: 2x - 4 = 0 ; and u still get x = 2 yet another way to factorise: (x-2) and (2x-2) and yet again u get 1 and 2. Yet another solution is to divide each side of the equations by 2. 2/2 = 1 and 0/2 = 0 Capice? [This message was edited Sun Jan 18 16:45:22 PST 2004 by SpcMs] Thanks a lot! That's the right answer, there's what I was looking for. THANKYOU! That's my maths homework finished! Er, if that´s the right answer, then you didn´t describe the original equation right. "2" works in the equation but not "1"... | |
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Vibrator said: Spookymuffin said: SpcMs said: Since the two confuses u, i'll xplain:
u factorised the whole thing, right. Now, the righthandside is zero. To get the lefthandside to zero, all u have to do is get one of the factors to zero (since 0 times anything still equals zero). The factors u have are: (2) (x-2) and (x-1) so, the only two factors u can get to zero are (x-2) and (x-1) if u'r confused by the 2, look at it this way: the factors could also b (2x-4) and (x-1), right? u equal one of the factors to zero: 2x - 4 = 0 ; and u still get x = 2 yet another way to factorise: (x-2) and (2x-2) and yet again u get 1 and 2. Yet another solution is to divide each side of the equations by 2. 2/2 = 1 and 0/2 = 0 Capice? [This message was edited Sun Jan 18 16:45:22 PST 2004 by SpcMs] Thanks a lot! That's the right answer, there's what I was looking for. THANKYOU! That's my maths homework finished! Er, if that´s the right answer, then you didn´t describe the original equation right. "2" works in the equation but not "1"... U are right, the original factorisation (is that the correct word?) is wrong. It should have been (as 2the9s xplained) (x-2) and (x+0.5) I didn't check that, u just xplained what the 2 did to the result. "It's better 2 B hated 4 what U R than 2 B loved 4 what U R not."
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math bites Goat's ass... Hi Janey baby sister missed u | |
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U still don't have it quite yet.
SpcMs said: Vibrator said: Spookymuffin said: SpcMs said: Since the two confuses u, i'll xplain:
u factorised the whole thing, right. Now, the righthandside is zero. To get the lefthandside to zero, all u have to do is get one of the factors to zero (since 0 times anything still equals zero). The factors u have are: (2) (x-2) and (x-1) so, the only two factors u can get to zero are (x-2) and (x-1) if u'r confused by the 2, look at it this way: the factors could also b (2x-4) and (x-1), right? u equal one of the factors to zero: 2x - 4 = 0 ; and u still get x = 2 yet another way to factorise: (x-2) and (2x-2) and yet again u get 1 and 2. Yet another solution is to divide each side of the equations by 2. 2/2 = 1 and 0/2 = 0 Capice? [This message was edited Sun Jan 18 16:45:22 PST 2004 by SpcMs] Thanks a lot! That's the right answer, there's what I was looking for. THANKYOU! That's my maths homework finished! Er, if that´s the right answer, then you didn´t describe the original equation right. "2" works in the equation but not "1"... U are right, the original factorisation (is that the correct word?) is wrong. It should have been (as 2the9s xplained) (x-2) and (x+0.5) I didn't check that, u just xplained what the 2 did to the result. -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
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On a side-note, re Concha's Sexual Xperimentation at Eton question: I met Harry. Twice. He's an arrogant little penis, I really hated him; he thought he was so cool cause he was royalty and it got let out in the news that he smoked dope. Truth is, everyone at Eton smokes dope, it's just one of those things. Secondly, no, there was gay "experimentation" as you call it in the 1930s at Eton, but not any more. We have "socials" (trips to visit girls) every Sunday to keep us on the straight and narrow as it were. Not that I'm homophobic, but you can see the media, "Eton made my son turn GAY." So, no, I don't think old William ever did it with a man, nor have I, although there was tons of Sexual experimentation at my last school, which none of you will have heard of. 1st there was the discovery of masturbation when all of us were 11, and everyone was doing it - but then we needed fantasies, so along came searches for porn. After being corrupted by porn, we all kinda wondered what some of the stuff was, like how can head be pleasurable? Anyway, to cut a long story short, many of us tried out giving each other head for a while, including me (well, I got head, but never gave it ) | |
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