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Math Brain Teaser May have been posted before:
a = x a+a = a+x 2a = a+x 2a-2x = a+x-2x 2(a-x) = a+x-2x 2(a-x) = a-x 2 = 1 ??? -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
Still it's nice to know, when our bodies wear out, we can get another -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- | |
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wrong forum.....wait, wrong website! | |
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Music washes away from the soul the dust of everyday life. ~Berthold Auerbach | |
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this is my thing I love this kind of stuff.. | |
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Flowers2 said: this is my thing I love this kind of stuff..
So what's your answer then? It's too late at night for me to sit and figure out formulas. I probably wouldn't bother anyway | |
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obsessed said: Flowers2 said: this is my thing I love this kind of stuff..
So what's your answer then? It's too late at night for me to sit and figure out formulas. I probably wouldn't bother anyway I'm with you, it's late lol .. to get the energy to try to do formulas @ 1:25am will exhaust me more lol .. but I do love this.. | |
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it could be any number you want.
Wait....2=1??? [Edited 12/13/08 22:42pm] | |
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ArielB said: Wait....2=1???
I saw that and decided to figure this out tomorrow.. this requires energy I don't have right now.. | |
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I don't even understand one word. | |
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abierman said: wrong forum.....wait, wrong website!
Yeah, like one with smart people. ~throws stone~ | |
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Since a=x, a-x=0
So in the last term, where you divide the left and right part by a-x, you're divinding by zero, which is not possible. What'd I win? You don't scare me; i got kids | |
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AlfofMelmak said: Since a=x, a-x=0
So in the last term, where you divide the left and right part by a-x, you're divinding by zero, which is not possible. What'd I win? Doofus Of The Week Award! | |
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But seriously, I wish I had a brain like that.
Good one, Favourite Left Leg. | |
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Ahem, Urban dictionary:
doofus:
Someone who hasn't got a clue! They live in blissful ignorance of the world, fashion, personal hygiene and social skills. Perfect recipe for hairy legs You don't scare me; i got kids | |
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AlfofMelmak said: Since a=x, a-x=0
So in the last term, where you divide the left and right part by a-x, you're divinding by zero, which is not possible. What'd I win? I don't see any dividing done. Only multiplying. | |
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I don't really understand how this is a brain teaser. It's just wrong.
If a = x, then a-x=0 so 2(a-x) = a-x is 2(0) = 0 the last step made in the original post was dividing (a-x)/(a-x) and taking that to be one, but 0/0 is 0, of course. I'm sure Moonbeam or another math geek can provide a better technical explanation with proper terminology, but I'm pretty certain that's all there is to it in laymen's terms. [Edited 12/14/08 9:26am] | |
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damosuzuki said: I don't really understand how this is a brain teaser. It's just wrong.
If a = x, the a-x=0 so 2(a-x) = a-x is 2(0) = 0 the last step made in the original post was dividing (a-x)/(a-x) and taking that to be one, but 0/0 is 0, of course. I'm sure Moonbeam or another math geek can provide a better technical explanation with proper terminology, but I'm pretty certain that's all there is to it in laymen's terms. There's no dividing in the original post, just multiplying. I think the point of this math problem is that "a" could equal 2 and "x" could equal 1 (or vice versa) and all the equations would work out. But that doesn't mean that 2 equals 1. | |
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Efan said: damosuzuki said: I don't really understand how this is a brain teaser. It's just wrong.
If a = x, the a-x=0 so 2(a-x) = a-x is 2(0) = 0 the last step made in the original post was dividing (a-x)/(a-x) and taking that to be one, but 0/0 is 0, of course. I'm sure Moonbeam or another math geek can provide a better technical explanation with proper terminology, but I'm pretty certain that's all there is to it in laymen's terms. There's no dividing in the original post, just multiplying. I think the point of this math problem is that "a" could equal 2 and "x" could equal 1 (or vice versa) and all the equations would work out. But that doesn't mean that 2 equals 1. There's an 'implied' division in the last two steps to reduce the equation. To get from: 2(a-x) = a-x To 2 = 1 You have to take this step: [2(a-x)]/(a-x) = (a-x)/(a-x) Which if a >< x, would then prove that 2=1. But a=x, so both sides of the equation = 0. I may be wrong, but that's all I see there. [Edited 12/14/08 9:53am] | |
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Efan said: damosuzuki said: I don't really understand how this is a brain teaser. It's just wrong.
If a = x, the a-x=0 so 2(a-x) = a-x is 2(0) = 0 the last step made in the original post was dividing (a-x)/(a-x) and taking that to be one, but 0/0 is 0, of course. I'm sure Moonbeam or another math geek can provide a better technical explanation with proper terminology, but I'm pretty certain that's all there is to it in laymen's terms. There's no dividing in the original post, just multiplying. I think the point of this math problem is that "a" could equal 2 and "x" could equal 1 (or vice versa) and all the equations would work out. But that doesn't mean that 2 equals 1. And how about that last step, what happens there? 2(a-x)=a-x 2=1 The left term is divided by (a-x), to end up with 2. To keep equality between the left and right term, the latter also must be divided by (a-x), which indeed would be 1. But since a-x=0, you would be dividing by zero. You don't scare me; i got kids | |
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too much for my dumb brain | |
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AlfofMelmak said: Efan said: There's no dividing in the original post, just multiplying. I think the point of this math problem is that "a" could equal 2 and "x" could equal 1 (or vice versa) and all the equations would work out. But that doesn't mean that 2 equals 1. And how about that last step, what happens there? 2(a-x)=a-x 2=1 The left term is divided by (a-x), to end up with 2. To keep equality between the left and right term, the latter also must be divided by (a-x), which indeed would be 1. But since a-x=0, you would be dividing by zero. I could be totally looking at this wrong, but I didn't think these were steps; I thought they were individual equations. So the first one after a = x (a+a = a+x) is separate and doesn't have anything to do with the last one or any of the other ones. I thought that the point was just showing that you could do all of those equations using either 1 or 2. But you would have to have both a and x equal 1 or both a and x equal 2; you can't have them equal the two numbers at the same time. So it doesn't really seem like a brain teaser; just an oddity of how you can use both numbers to fit into these equations. Does that make sense? I could be totally off on what this is talking about... | |
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Efan said: AlfofMelmak said: And how about that last step, what happens there? 2(a-x)=a-x 2=1 The left term is divided by (a-x), to end up with 2. To keep equality between the left and right term, the latter also must be divided by (a-x), which indeed would be 1. But since a-x=0, you would be dividing by zero. I could be totally looking at this wrong, but I didn't think these were steps; I thought they were individual equations. So the first one after a = x (a+a = a+x) is separate and doesn't have anything to do with the last one or any of the other ones. I thought that the point was just showing that you could do all of those equations using either 1 or 2. But you would have to have both a and x equal 1 or both a and x equal 2; you can't have them equal the two numbers at the same time. So it doesn't really seem like a brain teaser; just an oddity of how you can use both numbers to fit into these equations. Does that make sense? I could be totally off on what this is talking about... These are a series of steps, of equations. This is where the equation gets "zeroed" out: 2a-2x = a+x-2x At this point, they've made the equation state 0 = 0, and it carries through until the last step, where they "lie" to you by stating that 0/0=1, not 0. | |
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damosuzuki said: Efan said: I could be totally looking at this wrong, but I didn't think these were steps; I thought they were individual equations. So the first one after a = x (a+a = a+x) is separate and doesn't have anything to do with the last one or any of the other ones. I thought that the point was just showing that you could do all of those equations using either 1 or 2. But you would have to have both a and x equal 1 or both a and x equal 2; you can't have them equal the two numbers at the same time. So it doesn't really seem like a brain teaser; just an oddity of how you can use both numbers to fit into these equations. Does that make sense? I could be totally off on what this is talking about... These are a series of steps, of equations. This is where the equation gets "zeroed" out: 2a-2x = a+x-2x At this point, they've made the equation state 0 = 0, and it carries through until the last step, where they "lie" to you by stating that 0/0=1, not 0. If I had a gif of Emily Littella saying, "Oh, that's different. Never mind!" I would post it here. I misunderstood, so disregard what I was saying. | |
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Efan said: AlfofMelmak said: And how about that last step, what happens there? 2(a-x)=a-x 2=1 The left term is divided by (a-x), to end up with 2. To keep equality between the left and right term, the latter also must be divided by (a-x), which indeed would be 1. But since a-x=0, you would be dividing by zero. I could be totally looking at this wrong, but I didn't think these were steps; I thought they were individual equations. So the first one after a = x (a+a = a+x) is separate and doesn't have anything to do with the last one or any of the other ones. I thought that the point was just showing that you could do all of those equations using either 1 or 2. But you would have to have both a and x equal 1 or both a and x equal 2; you can't have them equal the two numbers at the same time. So it doesn't really seem like a brain teaser; just an oddity of how you can use both numbers to fit into these equations. Does that make sense? I could be totally off on what this is talking about... Every line is exactly the same as the next; You can rewrite every equation as long as you do the same to the left as the right part of the equation. so to: a = x is added an a to both sides of the = -> a+a = a+x, then rewrite to 2a = a+x now substract 2x both left and right. 2a-2x = a+x-2x rewrites to 2(a-x) = a+x-2x 2(a-x) = a-x so this equation is exactly the same as a=x And it doesn't matter which number a or x is, it's the same. It has nothing to do with them being 1 or 2. if x = 0, so is a: fill in the last equation: 2(0) = 0 if x = 1, so is a: fill in the last equation: 2(0) = 0 if x = 11224868632433432.93278482764832648, so is a: fill in the last equation: 2(0) = 0 The teaser is in the last 2 lines; going from 2(a-x) to just 2, you would have to divide by (a-x). If the first line would have read a-x=0, you would have immediately seen the solution, but instead it was shown as a=x You don't scare me; i got kids | |
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AlfofMelmak said: Efan said: I could be totally looking at this wrong, but I didn't think these were steps; I thought they were individual equations. So the first one after a = x (a+a = a+x) is separate and doesn't have anything to do with the last one or any of the other ones. I thought that the point was just showing that you could do all of those equations using either 1 or 2. But you would have to have both a and x equal 1 or both a and x equal 2; you can't have them equal the two numbers at the same time. So it doesn't really seem like a brain teaser; just an oddity of how you can use both numbers to fit into these equations. Does that make sense? I could be totally off on what this is talking about... Every line is exactly the same as the next; You can rewrite every equation as long as you do the same to the left as the right part of the equation. so to: a = x is added an a to both sides of the = -> a+a = a+x, then rewrite to 2a = a+x now substract 2x both left and right. 2a-2x = a+x-2x rewrites to 2(a-x) = a+x-2x 2(a-x) = a-x so this equation is exactly the same as a=x And it doesn't matter which number a or x is, it's the same. It has nothing to do with them being 1 or 2. if x = 0, so is a: fill in the last equation: 2(0) = 0 if x = 1, so is a: fill in the last equation: 2(0) = 0 if x = 11224868632433432.93278482764832648, so is a: fill in the last equation: 2(0) = 0 The teaser is in the last 2 lines; going from 2(a-x) to just 2, you would have to divide by (a-x). If the first line would have read a-x=0, you would have immediately seen the solution, but instead it was shown as a=x Co-sign. | |
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-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
Still it's nice to know, when our bodies wear out, we can get another -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- | |
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mcmeekle said: Co-sign. You don't scare me; i got kids | |
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zero point zero | |
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im lost Smurf theme song-seriously how many fucking "La Las" can u fit into a dam song
Proud Wendy and Lisa Fancy Lesbian asskisser | |
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I divided x by 2 and got > <
| |
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